[LeetCode 58] Length of Last Word
LeetCode 58 (Java)
[Length of Last Word] 문제 풀이
[LeetCode 58] Length of Last Word
Description
Given a string s consisting of words and spaces, return the length of the last word in the string.
A word is a maximal substring consisting of non-space characters only.
Example 1
- Input: s = “Hello World”
- Output: 5
- Explanation: The last word is “World” with length 5.
Example 2
- Input: s = “ fly me to the moon “
- Output: 4
- Explanation: The last word is “moon” with length 4.
Example 3
- Input: s = “luffy is still joyboy”
- Output: 6
- Explanation: The last word is “joyboy” with length 6.
Constraints
1 <= s.length <= 10^4sconsists of only English letters and spaces' '.- There will be at least one word in
s.
Code
내 제출
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import java.util.*;
class Solution {
public int lengthOfLastWord(String s) {
StringTokenizer st = new StringTokenizer(s, " ");
List<String> list = new ArrayList<>();
while (st.hasMoreTokens()) {
list.add(st.nextToken());
}
//bw.write((list.get(list.size() - 1)).length());
return (list.get(list.size() - 1)).length();
}
}
| Runtime | Memory |
|---|---|
| 1 ms | 41.7 MB |
다른 풀이
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class Solution {
public int lengthOfLastWord(String s) {
int i = s.length()-1;
int length = 0;
while(i>=0 && s.charAt(i)== ' '){
i--;
}
while(i>=0 && s.charAt(i) != ' '){
length++;
i--;
}
return length;
}
}
Reference
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