[LeetCode 2264] Largest 3-Same-Digit Number in String
LeetCode 2264 (Java)
[Largest 3-Same-Digit Number in String] 문제 풀이
[LeetCode 2264] Largest 3-Same-Digit Number in String
Description
You are given a string num representing a large integer. An integer is good if it meets the following conditions:
- It is a substring of
numwith length3. - It consists of only one unique digit.
Return the maximum good integer as a string or an empty string "" if no such integer exists.
Note:
- A substring is a contiguous sequence of characters within a string.
- There may be leading zeroes in
numor a good integer.
Example 1
- Input: num = “6777133339”
- Output: “777”
- Explanation:
- There are two distinct good integers: “777” and “333”.
- “777” is the largest, so we return “777”.
Example 2
- Input: num = “2300019”
- Output: “000”
- Explanation: “000” is the only good integer.
Example 3
- Input: num = “42352338”
- Output: “”
- Explanation:
- No substring of length 3 consists of only one unique digit. Therefore, there are no good integers.
Constraints
3 <= num.length <= 1000numonly consists of digits.
Hint
Hint 1
We can sequentially check if “999”, “888”, “777”, … , “000” exists in num in that order. The first to be found is the maximum good integer.
Hint 2
If we cannot find any of the above integers, we return an empty string “”.
Code
내 제출
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class Solution {
public String largestGoodInteger(String num) {
for (int i = 9; i >= 0; i--) {
String s = String.valueOf(i).repeat(3);
if (num.contains(s)) {
return s;
}
}
return "";
}
}
| Runtime | Memory |
|---|---|
| 1 ms | 41.9 MB |
다른 풀이
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class Solution {
public String largestGoodInteger(String num) {
String[] toFind = new String[]{"999", "888", "777", "666", "555", "444", "333", "222", "111", "000"};
for (String ans : toFind) {
if (num.contains(ans)) return ans;
}
return "";
}
}
Reference
- https://github.com/doocs/leetcode/blob/main/solution/2200-2299/2264.Largest%203-Same-Digit%20Number%20in%20String/Solution.java
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