[LeetCode 104] Maximum Depth of Binary Tree
LeetCode 104 (Java)
[Maximum Depth of Binary Tree] 문제 풀이
[LeetCode 104] Maximum Depth of Binary Tree
Description
Given the root of a binary tree, return its maximum depth.
A binary tree’s maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1
- Input: root = [3,9,20,null,null,15,7]
- Output: 3
Example 2
- Input: root = [1,null,2]
- Output: 2
Constraints
- The number of nodes in the tree is in the range
[0, 104]. -100 <= Node.val <= 100
Code
내 제출
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int maxDepth(TreeNode root) {
if (root == null) {
return 0;
}
int l = maxDepth(root.left);
int r = maxDepth(root.right);
return 1 + Math.max(l, r);
}
}
| Runtime | Memory |
|---|---|
| 0 ms | 43.4 MB |
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class Solution {
public int maxDepth(TreeNode root) {
if (root == null) {
return 0;
}
Queue<TreeNode> queue = new LinkedList<>();
queue.add(root);
int depth = 0;
while (!queue.isEmpty()) {
depth++;
int levelSize = queue.size();
for (int i = 0; i < levelSize; i++) {
TreeNode node = queue.poll();
if (node.left != null) {
queue.add(node.left);
}
if (node.right != null) {
queue.add(node.right);
}
}
}
return depth;
}
}
Reference
- https://github.com/doocs/leetcode/blob/main/solution/0100-0199/0104.Maximum%20Depth%20of%20Binary%20Tree/Solution.java
This post is licensed under CC BY 4.0 by the author.

