[LeetCode 100] Same Tree
LeetCode 100 (Java)
[Same Tree] 문제 풀이
[LeetCode 100] Same Tree
Description
Given the roots of two binary trees p and q, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.
Example 1
- Input: p = [1,2,3], q = [1,2,3]
- Output: true
Example 2
- Input: p = [1,2], q = [1,null,2]
- Output: false
Example 3
- Input: p = [1,2,1], q = [1,1,2]
- Output: false
Constraints
- The number of nodes in both trees is in the range
[0, 100]. -10^4 <= Node.val <= 10^4
Code
내 제출
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if (p == q) return true;
if (p == null || q == null || p.val != q.val) return false;
return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
}
}
| Runtime | Memory |
|---|---|
| 0 ms | 40.9 MB |
다른 풀이
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if(p==null && q==null)
{
return true;
}
if(p==null || q==null)
{
return false;
}
if((p.val == q.val) && isSameTree(p.left, q.left) && isSameTree(p.right, q.right))
{
return true;
}
else
{
return false;
}
}
}
Reference
- https://github.com/doocs/leetcode/blob/main/solution/0100-0199/0100.Same%20Tree/Solution.java
This post is licensed under CC BY 4.0 by the author.



